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Python code

Here is a code quadratic.py that calculates roots of a quadratic according to the method discussed above.

#! /usr/local/bin/python3
import math

# Compute the real roots of the quadratic equation 
# This algorithm does not handle exceptional cases 

# Ask the user for a, b, and c and get them 
print("Solving the quadratic equation ax^2 + bx + c")
a, b, c = eval(input("Enter a, b, c "))

# Compute the "discriminant"
d = b*b - 4*a*c

# Get the sign of b 
signb = 1
if b < 0:
    signb = -1

# Avoid loss of significance here by making the sign of the sqrt match 
# the sign of b 
s = -(b + math.sqrt(d)*signb)/2.

# Use one formula for the first root and the other for the second 
x1 = s/a
x2 = c/s

print("Roots are", x1, " ", x2)

Try running the code with an example of your choosing.



Carleton DeTar 2017-09-05